# III.- Más ejercicios

 871. $\dpi{50}&space;5x+9+\frac{x}{3}=8x-7$
 872. $\dpi{50}&space;\frac{x}{4}+3=\frac{3x}{5}+2-\frac{x}{3}$
 873. $\dpi{50}&space;\frac{x-9}{x+3}=\frac{4}{x+3}-5$
 874. $\dpi{50}&space;\frac{\frac{3x}{7}.16}{x+1}=6$
 875. $\dpi{50}&space;\frac{2}{x+1}=\frac{x}{x-1}-1$
 876. $\dpi{50}&space;\frac{7x}{8}-5(x-9)=\frac{20x+1,5}{6}$
 877. $\dpi{50}&space;\frac{0,15x-1}{0,20(x-3)}=\frac{1}{2}$
 878. $\dpi{50}&space;x+\frac{x+4}{5}=1+\frac{x}{2}$
 879. $\dpi{50}&space;9x-\frac{7-x}{8}=10+\frac{x}{4}+2x$
 880. $\dpi{50}&space;\frac{3}{5}-\frac{7x}{10}+\frac{3x}{4}-\frac{7x}{8}=-9$
 881. $\dpi{50}&space;\frac{x+1}{2}+\frac{5+x}{6}=1+\frac{x+1}{3}$
 882. $\dpi{50}&space;4-\frac{x+3}{6}=2+\frac{9-2x}{3}$
 883. $\dpi{50}&space;\frac{3x}{5}-\frac{7x}{10}+\frac{3x}{4}-\frac{7x}{8}+18=0$
 884. $\dpi{50}&space;\frac{30}{x+5}+\frac{5+4x}{x+5}=5$
 885. $\dpi{50}&space;\frac{x+8}{x-1}-\frac{x+4}{x+1}=\frac{12x}{x^{2}-1}$
 886. $\dpi{50}&space;\frac{5x-3}{6}-\frac{7x-1}{4}=\frac{4x+2}{7}-5$
 887. $\dpi{50}&space;\frac{3(2x+1)}{4}-\frac{5x+3}{6}+4x+\frac{x+1}{3}=x+\frac{151}{12}$
 888. $\dpi{50}&space;\frac{3x}{5}+2-\frac{x}{3}=\frac{x}{4}+3$
 889. $\dpi{50}&space;\frac{10}{x+10}-\frac{5}{x+2}=0$
 890. $\dpi{50}&space;\frac{20}{x+1}+\frac{5x-5}{x^{2}-1}=\frac{52}{x-1}-\frac{40}{x+1}$
 891. $\dpi{50}&space;\frac{3(2x+1)}{4}-\frac{3x}{10}-5=\frac{2(3x-1)}{5}-\frac{11x}{20}$
 892. $\dpi{50}&space;\frac{15}{x-1}-\frac{10}{x+4}=\frac{100}{x^{2}+3x-4}$
 893. $\dpi{50}&space;\frac{15}{x-2}-\frac{12x+6}{2x^{2}-8}=\frac{18}{x+2}$
 894. $\dpi{50}&space;(a+x)(b+x)-a(b+c)-x^{2}=\frac{a^{2}c}{b}$
 895. $\dpi{50}&space;\frac{1}{x-a}+\frac{1}{x+a}=\frac{1}{x^{2}-a^{2}}$
 896. $\dpi{50}&space;x+\frac{x}{2a}-1=\frac{1+x}{2}$
 897. $\dpi{50}&space;\frac{5x^{n}}{x+1}+\frac{5x^{n}+11x^{n+2}}{x^{2}-1}=\frac{10x^{n+1}}{x-1}$
 898. $\dpi{50}&space;\frac{2+\frac{x+1}{x-1}}{1-\frac{x-1}{x+1}}=\frac{3x}{2}$
 899. $\dpi{50}&space;\frac{2}{x+\frac{1}{1+\frac{x+1}{x-2}}}=\frac{6}{3x-1}$
 900. $\dpi{100}&space;\large&space;\frac{\frac{x-3}{2}-\frac{x-3}{4}}{x-\frac{1}{3-\frac{3x-1}{x+1}}}$$=\frac{1}{11}$

Soluciones